本文共 1303 字，大约阅读时间需要 4 分钟。

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

注：题库和图片转自 www.leetcode.com ，所有权归www.leetcode.com仅供交流学习使用，不得用于商业用途

-----------------------------------------------------------------------------------------------------

/** * Definition for a binary tree node. * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public:    int maxDepth(TreeNode* root) {        int currentDepth = 0;        maxDep = 0;        if(root != NULL)        {            travelBinaryTree(root, currentDepth);        }        return maxDep;    }private:    int maxDep;    void travelBinaryTree(TreeNode* node, int depth)    {        depth++;        maxDep = (depth > maxDep) ? depth : maxDep;        if(node->left)            travelBinaryTree(node->left, depth);        if(node->right)            travelBinaryTree(node->right, depth);    }};

class Solution {public:    int maxDepth(TreeNode* root) {        if (!root)            return 0;        return 1 + max(maxDepth(root->right), maxDepth(root->left));    }};

转载地址：http://ltbg.baihongyu.com/